2400x-16X^2=600

Solution for 2400x-16X^2=600 equation:

2400x-16x^2=600

We move all terms to the left:

2400x-16x^2-(600)=0

a = -16; b = 2400; c = -600;
Δ = b2-4ac
Δ = 24002-4·(-16)·(-600)
Δ = 5721600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5721600}=\sqrt{6400*894}=\sqrt{6400}*\sqrt{894}=80\sqrt{894}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2400)-80\sqrt{894}}{2*-16}=\frac{-2400-80\sqrt{894}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2400)+80\sqrt{894}}{2*-16}=\frac{-2400+80\sqrt{894}}{-32}
$